Solve Quadratic equations x2+x-756=0 Tiger Algebra Solver (2024)

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "x2" was replaced by "x^2".

Step by step solution :

Step 1 :

Trying to factor by splitting the middle term

1.1Factoring x2+x-756

The first term is, x2 its coefficient is 1.
The middle term is, +x its coefficient is 1.
The last term, "the constant", is -756

Step-1 : Multiply the coefficient of the first term by the constant 1-756=-756

Step-2 : Find two factors of -756 whose sum equals the coefficient of the middle term, which is 1.

-756+1=-755
-378+2=-376
-252+3=-249
-189+4=-185
-126+6=-120
-108+7=-101
-84+9=-75
-63+12=-51
-54+14=-40
-42+18=-24
-36+21=-15
-28+27=-1
-27+28=1That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step2above, -27 and 28
x2 - 27x+28x - 756

Step-4 : Add up the first 2 terms, pulling out like factors:
x•(x-27)
Add up the last 2 terms, pulling out common factors:
28•(x-27)
Step-5:Add up the four terms of step4:
(x+28)•(x-27)
Which is the desired factorization

Equation at the end of step 1 :

 (x + 28) • (x - 27) = 0 

Step 2 :

Theory - Roots of a product :

2.1 A product of several terms equals zero.When a product of two or more terms equals zero, then at least one of the terms must be zero.We shall now solve each term = 0 separatelyIn other words, we are going to solve as many equations as there are terms in the productAny solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation:

2.2Solve:x+28 = 0Subtract 28 from both sides of the equation:
x = -28

Solving a Single Variable Equation:

2.3Solve:x-27 = 0Add 27 to both sides of the equation:
x = 27

Supplement : Solving Quadratic Equation Directly

Solving x2+x-756 = 0 directly 

Earlier we factored this polynomial by splitting the middle term. let us now solve the equation by Completing The Square and by using the Quadratic Formula

Parabola, Finding the Vertex:

3.1Find the Vertex ofy = x2+x-756Parabolas have a highest or a lowest point called the Vertex.Our parabola opens up and accordingly has a lowest point (AKA absolute minimum).We know this even before plotting "y" because the coefficient of the first term,1, is positive (greater than zero).Each parabola has a vertical line of symmetry that passes through its vertex. Because of this symmetry, the line of symmetry would, for example, pass through the midpoint of the two x-intercepts (roots or solutions) of the parabola. That is, if the parabola has indeed two real solutions.Parabolas can model many real life situations, such as the height above ground, of an object thrown upward, after some period of time. The vertex of the parabola can provide us with information, such as the maximum height that object, thrown upwards, can reach. For this reason we want to be able to find the coordinates of the vertex.For any parabola,Ax2+Bx+C,the x-coordinate of the vertex is given by -B/(2A). In our case the x coordinate is -0.5000Plugging into the parabola formula -0.5000 for x we can calculate the y-coordinate:
y = 1.0 * -0.50 * -0.50 + 1.0 * -0.50 - 756.0
or y = -756.250

Parabola, Graphing Vertex and X-Intercepts :

Root plot for : y = x2+x-756
Axis of Symmetry (dashed) {x}={-0.50}
Vertex at {x,y} = {-0.50,-756.25}
x-Intercepts (Roots) :
Root 1 at {x,y} = {-28.00, 0.00}
Root 2 at {x,y} = {27.00, 0.00}

Solve Quadratic Equation by Completing The Square

3.2Solvingx2+x-756 = 0 by Completing The Square.Add 756 to both side of the equation :
x2+x = 756

Now the clever bit: Take the coefficient of x, which is 1, divide by two, giving 1/2, and finally square it giving 1/4

Add 1/4 to both sides of the equation :
On the right hand side we have:
756+1/4or, (756/1)+(1/4)
The common denominator of the two fractions is 4Adding (3024/4)+(1/4) gives 3025/4
So adding to both sides we finally get:
x2+x+(1/4) = 3025/4

Adding 1/4 has completed the left hand side into a perfect square :
x2+x+(1/4)=
(x+(1/2))(x+(1/2))=
(x+(1/2))2
Things which are equal to the same thing are also equal to one another. Since
x2+x+(1/4) = 3025/4 and
x2+x+(1/4) = (x+(1/2))2
then, according to the law of transitivity,
(x+(1/2))2 = 3025/4

We'll refer to this Equation as Eq. #3.2.1

The Square Root Principle says that When two things are equal, their square roots are equal.

Note that the square root of
(x+(1/2))2 is
(x+(1/2))2/2=
(x+(1/2))1=
x+(1/2)

Now, applying the Square Root Principle to Eq.#3.2.1 we get:
x+(1/2)= 3025/4

Subtract 1/2 from both sides to obtain:
x = -1/2 + √ 3025/4

Since a square root has two values, one positive and the other negative
x2 + x - 756 = 0
has two solutions:
x = -1/2 + √ 3025/4
or
x = -1/2 - √ 3025/4

Note that 3025/4 can be written as
3025 / √4which is 55 / 2

Solve Quadratic Equation using the Quadratic Formula

3.3Solvingx2+x-756 = 0 by the Quadratic Formula.According to the Quadratic Formula,x, the solution forAx2+Bx+C= 0 , where A, B and C are numbers, often called coefficients, is given by :

-B± √B2-4AC
x = ————————
2A
In our case,A= 1
B= 1
C=-756
Accordingly,B2-4AC=
1 - (-3024) =
3025
Applying the quadratic formula :

-1 ± √ 3025
x=——————
2
Can 3025 be simplified ?

Yes!The prime factorization of 3025is
5•5•11•11
To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).

3025 =√5•5•11•11 =5•11•√ 1 =
±55 •√ 1 =
±55

So now we are looking at:
x=(-1±55)/2

Two real solutions:

x =(-1+√3025)/2=(-1+55)/2= 27.000

or:

x =(-1-√3025)/2=(-1-55)/2= -28.000

Two solutions were found :

  1. x = 27
  2. x = -28
Solve Quadratic equations x2+x-756=0 Tiger Algebra Solver (2024)

FAQs

How do I solve this quadratic equation? ›

Solve a quadratic equation using the quadratic formula.
  1. Write the quadratic equation in standard form, ax2 + bx + c = 0. Identify the values of a, b, and c.
  2. Write the Quadratic Formula. Then substitute in the values of a, b, and c.
  3. Simplify.
  4. Check the solutions.

How to factor a quadratic equation? ›

Factorization of Quadratic Equations
  1. Learn: Factorisation. ...
  2. Step 1: Consider the quadratic equation ax2 + bx + c = 0.
  3. Step 2: Now, find two numbers such that their product is equal to ac and sum equals to b. ...
  4. Step 3: Now, split the middle term using these two numbers, ...
  5. Step 4: Take the common factors out and simplify.

What is the formation of the quadratic equation? ›

A quadratic has the standard form y = ax² + bx + c, where a, b, and c are all numbers and a cannot be zero.

What is the quadratic formula explained? ›

In math, we define a quadratic equation as an equation of degree 2, meaning that the highest exponent of this function is 2. The standard form of a quadratic is y = ax^2 + bx + c, where a, b, and c are numbers and a cannot be 0. Examples of quadratic equations include all of these: y = x^2 + 3x + 1.

How to solve a quadratic equation trick? ›

Top 3 Tips to solve Quadratic Equations in Bank Exams

Once it has no remaining terms we can write zero. The second step is to factor the equation so that there is a set each through the middle term break method. The last part is to separate each factor set to zero. and solve putting the equations in this.

What are the 4 steps to solve a quadratic equation? ›

Solving Quadratic Equations
  • Put all terms on one side of the equal sign, leaving zero on the other side.
  • Factor.
  • Set each factor equal to zero.
  • Solve each of these equations.
  • Check by inserting your answer in the original equation.

How to solve quadratic equations by factoring fast? ›

To solve an quadratic equation using factoring :
  1. Transform the equation using standard form in which one side is zero.
  2. Factor the non-zero side.
  3. Set each factor to zero (Remember: a product of factors is zero if and only if one or more of the factors is zero).
  4. Solve each resulting equation.

How to simplify a quadratic equation? ›

Step 1: Using inverse operations, move all terms to one side of your equal sign. Step 2: Simplify your equation, and move terms around so that your equation is in the standard form of a quadratic function. Step 3: Now that your equation is in standard form, you can determine the values for a, b, and c.

How to find the roots of a quadratic equation? ›

For a quadratic equation ax2 + bx + c = 0, The roots are calculated using the formula, x = (-b ± √ (b2 - 4ac) )/2a.

How do you form a quadratic equation? ›

The quadratic equation in its standard form is ax2 + bx + c = 0, where a and b are the coefficients, x is the variable, and c is the constant term. The important condition for an equation to be a quadratic equation is the coefficient of x2 is a non-zero term (a ≠ 0).

Who invented algebra? ›

Muhammad ibn Musa Al-Khwarizmi: The Father of Algebra | Lowell Milken Center.

What are the five examples of a quadratic equation? ›

Examples of quadratic equations
  • x 2 + x − 30 = 0.
  • 5 t 2 + 4 t + 1 = 0.
  • 16 x 2 − 4 = 0.
  • 3 x 2 + x = 0.
  • 5 x 2 = 25.

How to solve a quadratic formula step by step? ›

HowTo: Solve a Quadratic Equation Using the Quadratic Formula
  1. Write the quadratic equation in standard form, ax2+bx+c=0. Identify the values of a,b, and c.
  2. Write the Quadratic Formula. Then substitute in the values of a,b, and c.
  3. Simplify.
  4. Check the solutions.
Aug 23, 2020

What is a quadratic equation for dummies? ›

A quadratic equation is any second degree polynomial equation — that's when the highest power of x, or whatever other variable is used, is 2. You can solve quadratic equations by factoring. Bring all terms to one side of the equation, leaving a zero on the other side.

What are the 4 methods of solving quadratic equations? ›

Answer: There are various methods by which you can solve a quadratic equation such as: factorization, completing the square, quadratic formula, and graphing. These are the four general methods by which we can solve a quadratic equation.

How to find the equation of a quadratic function? ›

A quadratic function, of the form f(x) = ax2 + bx + c, is determined by three points. Given three points on the graph of a quadratic function, we can work out the function by finding a, b and c algebraically. This will require solving a system of three equations in three unknowns.

How to find a quadratic equation from points? ›

If You are given three points Just use the equation y=a(x-h)^2+k. Now you need to put your points in the above equation (in place of x,y) and solve equations for the values of a,h,k. Finally, You get a Quadratic Function.

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